3t^2+30t-72=0

Solution for 3t^2+30t-72=0 equation:

3t^2+30t-72=0

a = 3; b = 30; c = -72;
Δ = b2-4ac
Δ = 302-4·3·(-72)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-42}{2*3}=\frac{-72}{6}
=-12
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+42}{2*3}=\frac{12}{6}
=2
$